|1/3-1/2|+|1/4-1/3|+|1/5-1/4|+|1/6-1/5|+|1/7-1/6|+|1/8-1/7|+|1/9-1/8|+1/10-1/9|=
来源:百度知道 编辑:UC知道 时间:2024/06/16 05:42:03
我需要解题的过程!谢谢!
解:
由题可知
1/3-1/2<0
1/4-1/3<0
1/5-1/4<0
……
1/10-1/9<0
所以原式=-(1/3-1/2)-(1/4-1/3)-(1/5-1/4)-……-(1/10-1/9)
=1/2-1/3+1/3-1/4+1/4-1/5+……+1/9-1/10
=1/2-1/10
=2/5
直接去掉绝对值符号,很多项就互相抵消了
结果是2/5
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
1+1/(1+2)+1/(1+2+3)+-------+1/(1+2+3+----+100)
1+1/2+1/3+.....+1/n
1+1/2+1/3+...+1/100
1-1/2+1/3-.....-1/10
(1+1/2+1/3+1/4)×
1+1/1+2+1/1+2+3+...+1/1+2+3...+2000
1*(1/1+2)*(1/1+2+3)*~~~*(1/1+2+~~~2005)=?
(1-1/2)(1-1/3)(1-1/4)(1-1/5).....(1-1/1000)